4 ms·

a_int and b_int are signed values.

• rep_lodsb 8mo ago
  It makes no difference whether they're signed or unsigned. Unless the subtraction is checking for overflow, or using a wider integer type than the numbers being compared, the high bit will not in every case indicate which number is smaller. e.g. 0x8000_0000 < 0x0000_0001 for signed numbers 0x8000_0000 - 0x0000_0001 = 0x7fff_ffff, high bit clear
  • jedisct1 8mo ago
    They are using a wider type.
    • rep_lodsb 8mo ago
      Yes, looking at the source code on GitHub now cleared that up! Didn't see it mentioned in the article though, maybe I missed it. If not, I think that this detail would be a good thing to include, both since it's a common mistake that others with less experience might make, and to get ahead of nitpicky comments like mine :)