4 ms·
If there did, it'd be a distinguisher attack on that CSPRNG. So for a non-broken CSPRNG, the answer is "no", by the definition of "non-broken CSPRNG".
by SAI_Peregrinus 8mo ago
If there did, it'd be a distinguisher attack on that CSPRNG. So for a non-broken CSPRNG, the answer is "no", by the definition of "non-broken CSPRNG".