3 ms·> Already, we have a factor of O(log(n)) here. Doesn’t that mean that O(log(n)) is really O(log²(n))?by layer8 9mo ago> Already, we have a factor of O(log(n)) here. Doesn’t that mean that O(log(n)) is really O(log²(n))?thfuran 9mo agoYou have to define what n is.layer8 9mo agoIt’s clear from the parent comment that the number of bits needed to represent the input is meant here.