4 ms·
> let weighted_reward = (volume_factor * 0.4) + (count_factor * 0.3) + 0.3; > MIN_BLOCK_REWARD + ((current_max - MIN_BLOCK_REWARD) * wei
by tromp 8mo ago
> let weighted_reward = (volume_factor * 0.4) + (count_factor * 0.3) + 0.3;
> MIN_BLOCK_REWARD + ((current_max - MIN_BLOCK_REWARD) * weighted_reward)
Making reward increase with tx count will strongly incentivize the miners to fill the blocks with dummy txs, needlessly wasting everyone's resources.
- invar1ant 8mo agoI agree with this so switching to a fee‑weighted bonus so only economically meaningful activity increases reward. >let base_reward = MIN_BLOCK_REWARD + ((current_max - MIN_BLOCK_REWARD) * (total_fees / fee_target).clamp(0.0, 1.0));
- tromp 8mo agoThat doesn't help (unless you burn a significant part of the fees), since the miner will just pay plenty fees on all the dummy txs that they simply end up paying to themselves.
- invar1ant 8mo agoOkay, now 35% of fees are clipped/burned. That directly addresses the concern because self‑fee recycling becomes clearly loss‑making, while miners still keep 65% of fees so fee incentives remain meaningful during demand spikes with 10‑second blocks and a 10–50 base reward range. ty for feedback btw