3 ms·
You're not using `integer` in the perl example like you're supposed to. Try perl -Minteger -E 'say ~-0' and it should work as expected.
by shawn_w 9mo ago
You're not using `integer` in the perl example like you're supposed to. Try
perl -Minteger -E 'say ~-0'
and it should work as expected.
- omoikane 9mo agoThat is true, but for the kind of code where I might use this trick, there usually aren't enough `~-$x` for `use integer;` to be worthwhile, I would just do `($x-1)` instead.