3 ms·
My understanding is that using `error` as a return type performs type erasure and that the only information given to the caller is the value of the `e.Error()`
by benrazdev 9mo ago
My understanding is that using `error` as a return type performs type erasure and that the only information given to the caller is the value of the `e.Error()` function. I now understand that this isn't the case.