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> The parent is correct, the claimed relationship being y ~ rank^a for some a<0 You clearly don't know the difference between exponential and polynomial relati
by rorrr 14y ago
> The parent is correct, the claimed relationship being y ~ rank^a for some a<0
You clearly don't know the difference between exponential and polynomial relationship.
rank^a is polynomial.
a^rank is exponential.
The data is neither (unless you can demonstrate it with the actual formula).
- hyperbovine 14y agoI don't really have time to do this because I'm supposed to be working on a paper about, wait for it, power laws, but I went ahead and re-plotted the data using log-log axes. Sure enough, it's linear as would be expected for power law type behavior: http://imgur.com/qdWxr http://imgur.com/qdWxr I suggest you start with http://www.hpl.hp.com/research/idl/papers/ranking/ranking.html http://www.hpl.hp.com/research/idl/papers/ranking/ranking.ht....
- rorrr 14y agoWell of course, pretty much any data looks linear on a log-log chart. The real question here is what the formula is between the rank and the number of views. You absolutely cannot derive it from the log-log chart. My point from the beginning is that it's not a power law (y=c*a^bx, where y = views, x = rank and the rest is constants).
- hyperbovine 14y ago> Well of course, pretty much any data looks linear on a log-log chart. Hah! If you seriously believe that, I've got some stock options I'd like to sell you...