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I agree, but actually, it's not even possible to draw a uniform 3D grid through the universe because of the curvature of spacetime. So even if the universe is a
by codeflo 14y ago
I agree, but actually, it's not even possible to draw a uniform 3D grid through the universe because of the curvature of spacetime. So even if the universe is a simulation, I don't think it could possibly work the way they describe and show the kind of artifact that they measure.
- gfodor 14y agoBe sure to email the physics PhDs who published this paper to let them know of this flaw you have found.
- codeflo 14y agoBe sure to leave it at that snide remark and not actually explain the flaw in my reasoning, so that I can avoid learning something.
- gfodor 14y agoThe point was you made a claim not a question. As snide as my remark might have been, you're insulting the people who did this research by being so matter-of-fact'ly dismissive of their work based upon a very basic observation that they surely must have considered.
- rayval 14y agoYes, it's possible that a simulation would use a non-uniform lattice-like data structure. Maybe something like a quad-tree (with appropriate dimensionality) where the granularity of the structure varies according to the local density of data. Granted, such a data structure would need to be expressed in a coordinate system, which itself defines a grid or matrix. But can't coordinate systems use non-uniform representations? (analogous to floating-point) Am neither physicist nor CS person, so not sure all of this holds together, just wondering.