3 ms·
I finally clicked when I worked out it was 2^64 subnets . You have a common prefix of you /48, which isn’t much longer than an ipv4 address - especially as it s
by hdgvhicv 10mo ago
I finally clicked when I worked out it was 2^64 subnets . You have a common prefix of you /48, which isn’t much longer than an ipv4 address - especially as it seems everything is 2001::/16, which means you basically have to remember a 32 bit network prefix just like 12.45.67.8/32.
That becomes 2001:0c2d:4308::/48 instead
After that you just need to remember the subnet number and the host number. If you remember 12.45.67.8 maps to 192.168.13.7 you might have
2001:0c2d:4308:13::7
So subnet “13” and host “7”
It’s not much different to remebering 12.45.67.8>192.168.13.7
- WarOnPrivacy 10mo ago> especially as it seems everything is 2001::/16 I was sort of expecting that this week. I had to transcribe a v6 addy for a WAN-WAN test (a few mi apart). That's when I noticed that Charter (Spectrum) had issued 2603:: for one WAN and 2602:: for the other WAN. ref: https://bgp.he.net/AS33363#_prefixes6 https://bgp.he.net/AS33363#_prefixes6
- themafia 10mo agoThe current global unicast space is actually limited to just 2000::/3. https://www.iana.org/assignments/ipv6-address-space/ipv6-address-space.xhtml https://www.iana.org/assignments/ipv6-address-space/ipv6-add...