3 ms·

I prefer a more generic form: (y-a)(y-b) = (x-c)(x-d)(x-k) By varying terms on both sides or making a term as a constant, you get generalizations for conics e

by zkmon 10mo ago

I prefer a more generic form: (y-a)(y-b) = (x-c)(x-d)(x-k) By varying terms on both sides or making a term as a constant, you get generalizations for conics etc.