3 ms·

use std::sync::Mutex; fn main() -> Result<(), Box<dyn std::error::Error>> { static PEDANTRY: Mutex<u64> = Mutex::new(0); *PEDANTRY.lock()? +

by raggi 10mo ago

use std::sync::Mutex; fn main() -> Result<(), Box<dyn std::error::Error>> { static PEDANTRY: Mutex<u64> = Mutex::new(0); *PEDANTRY.lock()? += 1; println!("{}", PEDANTRY.lock()?); Ok(()) }

hu3 10mo ago
Still different. Yours only increments once. Doesn't pass basic QA. And declaring a static variable inside a function, even if in main, smells.
- raggi 10mo ago
  OP you keep comparing to doesn't even declare the variable. I'm done with you.
  - School-Cotton 10mo ago
    OP here, not showing how to declare the variable was an oversight on my part. static mut COUNTER: u32 = 0; (at top-level) If on 2024 edition, you will additionally need #![allow(static_mut_refs)]
    - raggi 10mo ago
      Yup, your example was fine, as I said I just wanted to show a safe method too :-)