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Isabelle/HOL is still types. The underlying type theory of Isabelle/HOL is not theory of dependent types, but theory of simple types. Isabelle/ZF would be a be
by robinzfc 10mo ago
Isabelle/HOL is still types. The underlying type theory of Isabelle/HOL is not theory of dependent types, but theory of simple types.
Isabelle/ZF would be a better example as it encodes Zermelo–Fraenkel set theory.
- jfmc 10mo agoRight!