4 ms·
If you have some `ConstrainedNumber` type, you will need to cast between it and `number`, either with a type assertion or with a type guard. In either case, whe
by samdoesnothing 10mo ago
If you have some `ConstrainedNumber` type, you will need to cast between it and `number`, either with a type assertion or with a type guard. In either case, when you use bespoke types everywhere you kill code reuse.