3 ms·
Maybe you're just trolling, but rational numbers are numbers that can be expressed as p/q, where p and q are integers. Neither i e nor i is an integer, so your
by mhartl 14y ago
Maybe you're just trolling, but rational numbers are numbers that can be expressed as p/q, where p and q are integers. Neither i e nor i is an integer, so your proposed quotient has no bearing on the (ir)rationality of e.
- kdavis 14y agoI'll assume you are not trolling. My point is that log(-1)/(sqrt(-1)*log(e)) = ln(-1)/sqrt(-1) I am just writing the same equation using a log with another base so I don't have e in the equation explicitly.