4 ms·
So then wouldn't that make $|++ the variable name?
by Bratmon 11mo ago
So then wouldn't that make $|++ the variable name?
- broken-kebab 11mo agoSmokey, this is not 'Nam! This is <Perl>, there are rules! '$' guarantees a scalar. Then it either alphanumeric id, or a single non-alphanumeric symbol. And the latter means you deal with a 'special' var which with 100% certainty has a documentation entry.