4 ms·
If I remember correctly (I may not), two SHA-2 functions (SHA-224 and SHA-384?) aren't vulnerable to length extension attacks. While I agree with you that this
by apawloski 14y ago
If I remember correctly (I may not), two SHA-2 functions (SHA-224 and SHA-384?) aren't vulnerable to length extension attacks.
While I agree with you that this is an immediately important feature, I don't think Bruce's premise (that SHA-2 is still pretty good) is invalid.
Perhaps like you though, I don't understand why a new standard can't be incremental. I think it's silly to wait until something major happens to change.
- brazzy 14y agoThe problem with a new standard is that it may induce many to start using it on the grounds that "newer is better", which may not actually be the case: the SHA-2 algorithms have withstood more scrutiny so far.
- masklinn 14y ago> If I remember correctly (I may not), two SHA-2 functions (SHA-224 and SHA-384?) aren't vulnerable to length extension attacks. Interesting, is that because they only return part of the final state (by slicing sha-256 and sha-512) where unsliced 256 and 512 return all of the algorithm's running state as its result?