3 ms·
It's not that simple though. The rocket equation still applies so it's almost as hard to do (you just get rid of atmospheric drag), and failed launches are also
by literalAardvark 1y ago
It's not that simple though. The rocket equation still applies so it's almost as hard to do (you just get rid of atmospheric drag), and failed launches are also extra catastrophic.
Even more, your delta v required is still huge. I can't be bothered to run the numbers right now but most of the delta v is in the orbital velocity, not in the altitude.
- BobaFloutist 1y agoDelta v feels reductive, since your fighting negative acceleration to go up and a fraction of that to go laterally, no?
- lazide 1y agoThey’re the same thing. Either you go sideways really fast, or go straight up really far (geo-synchronous distance). Either way, you need the same total velocity delta.
- JumpCrisscross 1y ago> since your fighting negative acceleration to go up and a fraction of that to go laterally They’re both acceleration. At high thrust, virtually equivalent.