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Or, for a boolean type, that XOR is the same as the inequality operator.
by layer8 1y ago
Or, for a boolean type, that XOR is the same as the inequality operator.
- avalys 1y agoMaybe it’s confusing because it’s misnamed?
- ryandv 1y agoThis is like saying the non-negative integers under addition, lists under append, and strings under concatenation are all just misnamings of the semigroup operator. https://hackage.haskell.org/package/base-4.21.0.0/docs/Data-Monoid.html#v:-60--62- https://hackage.haskell.org/package/base-4.21.0.0/docs/Data-...
- layer8 1y agoIs it? Two things are equal exactly when they aren’t exclusive.