2 ms·
You're missing that the hash space is not divided uniformly. Which means one can vary the number of slots without recomputing the hash space division -- and wit
by zvr 1y ago
You're missing that the hash space is not divided uniformly. Which means one can vary the number of slots without recomputing the hash space division -- and without reassigning all of the existing entries.
- dataflow 1y agoI must've totally misunderstood what I read then. I'll give it another read, thanks!