3 ms·
Am I doing the math wrong here? You have a 50 character space, and a 10 character password length. This gives you 50^10, roughly 9.77 * 10^16, permutations. Ev
by AgentConundrum 14y ago
Am I doing the math wrong here? You have a 50 character space, and a 10 character password length. This gives you 50^10, roughly 9.77 * 10^16, permutations.
Even assuming you could store each possibility in a single byte, which you can't, that would still take about 86PB to store. Considering you would need to store both the key and the hash in order to have a useful table, it seems you would actually need to have a few exabytes dedicated to this.
- bcoates 14y agoGreenmountain's link below (and the Wikipedia page for Rainbow Table) cover it, but you do a space-for-speed tradeoff by basically re-hashing your hash repeatedly, and looking up if the result is in the table, which gives you a short-list of passwords from the pre-computed domain to try. There is a diminishing-returns limit to how small your rainbow table can be before it starts getting both false positives and false negatives, and bigger password domain makes it worse, but they require less than 1 bit per covered password.