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A relevant question on the Quantitative Finance StackExchange as to whether J/JDB can be used as an effective replacement for Q/KDB+ can be read here: http://qu
by lrm242 14y ago
A relevant question on the Quantitative Finance StackExchange as to whether J/JDB can be used as an effective replacement for Q/KDB+ can be read here: http://quant.stackexchange.com/questions/1870/can-the-j-language-be-used-as-an-effective-alternative-to-q-kdb http://quant.stackexchange.com/questions/1870/can-the-j-lang...
- sedachv 14y agoFrom what I understand, J has a lot of problems with efficient implementation because array ranks (multi-dimensional arrays) influence how operations are carried out (http://jsoftware.com/help/learning/07.htm http://jsoftware.com/help/learning/07.htm), and the ranks are not known in advance. [ranks also have horribly complicated semantics: http://www.jsoftware.com/papers/rank1.htm http://www.jsoftware.com/papers/rank1.htm] K doesn't have this problem because it only has vectors.