3 ms·Ruby in 83 chars: (1..100).map{|i|['fizzbuzz'].fetch(i%15,['fizz'].fetch(i%3,['buzz'].fetch(i%5,i)))}by glucero 14y agoRuby in 83 chars: (1..100).map{|i|['fizzbuzz'].fetch(i%15,['fizz'].fetch(i%3,['buzz'].fetch(i%5,i)))}