3 ms·Fizzbuzz without ifs in 90 char. I will buy you a beer if you can do better.4 points by alpb 14y agomattront 14y agoHere it is in 87 chars: [{0:"fizzbuzz"}.get(x%15,{0:"fizz"}.get(x%3,{0:"buzz"}.get(x%5,x)))for x in range(101)]glucero 14y agoRuby in 83 chars: (1..100).map{|i|['fizzbuzz'].fetch(i%15,['fizz'].fetch(i%3,['buzz'].fetch(i%5,i)))}