2 ms·
Damn - too much Perl coding recently, where + is always arithmetic. However, my point still stands: Why are some operators (and in particular unary minus, whic
by cygx 14y ago
Damn - too much Perl coding recently, where + is always arithmetic.
However, my point still stands: Why are some operators (and in particular unary minus, which is probably the most commonly used one) so much slower than others?
- some-1 14y agoSee the following comment: http://news.ycombinator.com/item?id=4530557 http://news.ycombinator.com/item?id=4530557 The reason why some of them is so fast is because the constant expression is evaluated to a constant, so instead of doing a conversion in the test, the already converted number is returned. Use this test instead: http://jsperf.com/parse-number-from-string http://jsperf.com/parse-number-from-string