4 ms·
The Probability and Statistics Cookbook
- jnazario 14y agomany thanks! this looks great and useful.
- chas 14y agoIf anyone is reading this and wants to know what it means, this is the best resource I have found for people with some math knowledge who want to develop a practical knowledge of statistics. http://www.itl.nist.gov/div898/handbook/ http://www.itl.nist.gov/div898/handbook/
- sidupadhyay 14y agoAlso, if you are interested in learning R while you build your knowledge of probability and statistics this is pretty good: http://ipsur.org/ http://ipsur.org/
- stiff 14y agoI also found StatSoft's statistics textbook to be useful: http://www.statsoft.com/textbook http://www.statsoft.com/textbook
- rheotron 14y agoHoly crap, I have a statistics exam on Wednesday and I was looking for something like this...Talk about lucky, thanks!
- sidupadhyay 14y agoThis really is a fairly thorough overview of an undergraduate statistics degree. It reminds me a lot the summaries I would write before exams. The first few sections covering probability are especially good. Though some of the later sections do simplify whole subjects a bit much. For example, an introduction to stochastic process (http://www.ma.utexas.edu/users/gordanz/notes/introduction_to_stochastic_processes.pdf http://www.ma.utexas.edu/users/gordanz/notes/introduction_to...) will cover more about state classification and absorption.
- pubby 14y agoThe pages of the pdf are too wide to fit comfortably on my screen. Any way I could fix it (like modify the LaTeX) besides buying a bigger monitor?
- tomrod 14y agoProbably a command called \landscape in the header. Look for that, then remove. LaTeX's default is A4 portrait, if I recall correctly. The source is on Github the website said.
- tomrod 14y agoThanks for posting this. It's most helpful!
- mturmon 14y agoThis covers a lot of ground, and is quite accurate and balanced. Very nice work. Kudos to the author. I noticed a couple of things. The graph of the F distribution on page 8 is mislabeled as chi-square. The sets Ai must be disjoint in the law of total prob. and Bayes rule on page 6. In section 5 on page 7, "variance of sum equals sum of variances" certainly does not imply ("iff") independence. I'm not positive it implies uncorrelated, although it certainly might. The safe thing is "variance of sum equals sum of variances" if uncorrelated. Uncorrelated is usually abbreviated with an inverted T (reminiscent of "orthogonal", although that abbreviation is not introduced in these notes). The inverted capital Pi used here means independence. A small typo: the Strong Law of Large Numbers is mis-abbreviated, it is the SLLN (sec. 10.1). And, neither the WLLN nor the SLLN requires Var(X1) < Infinity. They just need finite first moment ("E[X1] exists finite.") This is not an error in the notes, it's just that the result holds in more generality than is stated there, and the lack of need for a second moment shows the strength of the result (i.e., if the mean exists, you always get convergence to it, end of story). (This is in Billingsley's book, or Durrett's book, or also in http://www.math.ust.hk/~makchen/Math541/Chap1Sec7.pdf http://www.math.ust.hk/~makchen/Math541/Chap1Sec7.pdf as Thm 1.7.) Also, one omission: Brownian motion in Stochastic Processes (sec. 20). Since Poisson processes and Markov processes are there, it would make sense to have one continuous process. ("random walk" gets a couple of bullet points in sec. 21, but it's not the right place nor the right position.) All you need to define B.M., or a gaussian random process for that matter, is that B.M. is the continuous process with independent increments characterized by: X_0 = 0 X_t - X_s ~ N(0, t-s) for t > s Sec. 20.0 might also be a good place to introduce Kolmogorov's extension theorem (http://en.wikipedia.org/wiki/Kolmogorov_extension_theorem http://en.wikipedia.org/wiki/Kolmogorov_extension_theorem), since it is such a powerful result, is easy to state, and explains the centrality of finite-dimensional distributions.
- waldrews 14y agoVariance of sum equals sum of variances is not sufficient for pairwise uncorrelated for more than 2 random variables. Simplest counterargument is any Cov(A,B)=-Cov(B,C)!=0 for three variables. Closest results I can think of to the "iff" they're getting at: If sum var=var sum for all linear transformations of the individual variables (i.e. X_i -> a_i*X_i), that's sufficient for pairwise uncorrelated; If sum var=var sum for all transformations of the variables for which variances exist (i.e. X_i -> f_i(X_i)), that should be sufficient for independence (but I don't think that's an easy proof and maybe I'm missing technical conditions).
- amit_m 14y agoI wouldn't call it a cookbook. It is an (unusually large) cheatsheet.
- mavam 14y agoJohn D Cook's blog post actually inspired me to rename this work from cheatsheet to cookbook, as it outgrew the form factor of a classical printable cheatsheet. http://www.johndcook.com/blog/2010/10/04/probability-and-statistics-cheat-sheet/ http://www.johndcook.com/blog/2010/10/04/probability-and-sta...
- amit_m 14y agoA cookbook has recipes. If this is a cookbook, where are the recipes? :-) Such a concept might make sense in this context. e.g. Recipe to calculate p-values. How to fit various distributions. A recipe to calculate posterior probabilities, etc.