4 ms·
why? Also because x * 1/sqrt(x) == sqrt(x) (so on a pentium, an sqrt was 3 cycles further an inv-sqrt, pretty cheap for an sqrt)
by FredBrach 14y ago
why?
Also because x * 1/sqrt(x) == sqrt(x) (so on a pentium, an sqrt was 3 cycles further an inv-sqrt, pretty cheap for an sqrt)