3 ms·
Since the posting does not give a real answer. 192 is 11000000 in binary. So it is simply the block with the first two bits set in the netmask. 168 is a bit
by weinzierl 1y ago
Since the posting does not give a real answer.
192 is 11000000 in binary.
So it is simply the block with the first two bits set in the netmask.
168 is a bit more difficult. It is 10101000, a nice pattern but I don't know why this specific pattern.
- marcusb 1y agoI don't think this does anything to explain why 192.168/16 was chosen specifically. Three netblocks (10/8, 172.16/12, and 192.168/16) were selected from the class A, B, and C address spaces to accommodate private networks of various sizes. Class C addresses by definition have the two most significant bits set in their first octet and the third set to 0 (i.e., 192 - 223.) 192 in the first octet starts the class C space, but 10 and 172 do not have the same relationship in classes A and B.
- weinzierl 1y agoYes you are right. I researched a bit and there are other reserved blocks next the 168 that obviously don't have a nice pattern. So the 101010 is just a coincidence.
- drewolbrich 1y ago101010 in decimal is 42.
- temp0826 1y agoThat is the answer..!
- Hikikomori 1y ago192 is the first C class, 168 likely next available when rfc1918 was written.
- weinzierl 1y agoThis is the most likely thing that happened.