3 ms·
Hard to say. It is a write after free which rust technically prevents, but it depends on the abstractions chosen; it’s entirely likely there will be similar att
by vlovich123 1y ago
Hard to say. It is a write after free which rust technically prevents, but it depends on the abstractions chosen; it’s entirely likely there will be similar attacks that focus on exploiting flaws in the unsafe that will exist to trigger similar flaws. It should just be harder to exploit and easier to enforce that most of the kernel code is using “safe” abstractions.