4 ms·
Yea so overflow/underflow are a problem with signed integers, not unsigned ones. Promotion rules might be the only candidate for hidden complexity here I guess
by atiedebee 1y ago
Yea so overflow/underflow are a problem with signed integers, not unsigned ones. Promotion rules might be the only candidate for hidden complexity here I guess
- spacechild1 1y agoFirst, there is no integer underflow. Underflow is only possible with floating point numbers. Second, signed integer overflow is always undefined behavior whereas unsigned integer overflow is ok (= modulo behavior). The actual issue I was describing is about accidentally converting a negative (signed) integer to an unsigned integer, which completely changes its value. This is not a problem with signed or unsigned integers per se, but rather with the implicit conversions between these types. IMO this should have never been allowed in the first place.