The solutions to a⋅x² + b⋅x + c are given by x = (-b ± √(b² - 4⋅a⋅c)) / (2⋅a) φ ∩ (ψ ∪ ρ) ↔ (φ ∩ ψ) ∪ (φ ∩ ρ) Thanks! I can't even begin to describe how u

The solutions to a⋅x² + b⋅x + c are given by x = (-b ± √(b² - 4⋅a⋅c)) / (2⋅a) φ ∩ (ψ ∪ ρ) ↔ (φ ∩ ψ) ∪ (φ ∩ ρ) Thanks! I can't even begin to describe how useful this will be! If I could upvote this more than once, I would!