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He doesn't work with imaginary numbers, either. He treats complex numbers as matrices of rationals.
by empath75 1y ago
He doesn't work with imaginary numbers, either. He treats complex numbers as matrices of rationals.
- numpy-thagoras 1y agoWhich is the same thing for all intents and purposes. An ultrafinitist is still allowed to call that 'i'.
- dhosek 1y agoStill kind of freaked out that a Möbius transform can be expressed as a matrix multiplication.