3 ms·
Yep, you're correct. It should be (n+1)/(n+m+2). If you have access to a machine or lookup tables, you might as well plug in the values for the distribution Be
by yobbo 1y ago
Yep, you're correct. It should be (n+1)/(n+m+2).
If you have access to a machine or lookup tables, you might as well plug in the values for the distribution Beta(1+n,1+m) which should correspond to the joint density.
(The formula above corresponds to the mean of this distribution, so it's probably right but I haven't work it through myself now ...)
- usgroup 1y agoSee the Jeffrey posterior section here: https://en.m.wikipedia.org/wiki/Binomial_proportion_confidence_interval https://en.m.wikipedia.org/wiki/Binomial_proportion_confiden... The blog post uses a non informative Jeffrey prior.