3 ms·
200 phones a day doesn’t sound like that many given the size of the population and the number of tourists.
by iamacyborg 1y ago
200 phones a day doesn’t sound like that many given the size of the population and the number of tourists.
- arccy 1y agobut it could be like Tokyo....
- ubercow13 1y agoSupposedly 39% of phone thefts in Europe happen in the UK https://www.theguardian.com/technology/2025/jul/26/mobile-phone-theft-europe-uk-police https://www.theguardian.com/technology/2025/jul/26/mobile-ph...
- account42 1y agoWTF yes it does.
- selfhoster11 1y ago10 million people live in London. Surely you'd expect at least some theft of belongings
- deleted 1y ago[deleted]
- foldr 1y agoLet's do some back-of-an-envelope stats on this. Assuming there are 9 million people in London, that means that 1/45,000 Londoners experience a phone theft on a given day. We can then (very crudely) estimate the probability that a Londoner has their phone stolen over a ten year period: 1 - ((1-45000)/45000)^(365*10) = 0.08 So 200 phones a day translates to about a 8% chance of getting your phone stolen over a period of ten years. I'm obviously not suggesting that the calculation above be taken too seriously. But it shows that 200 phones being stolen a day in a city of 9 million people is consistent with phone theft being a significant but not overwhelming problem. (The adult population of London is around 7 million, and kids are obviously also victims of phone theft, so you won't get a radically different answer if you look at the population over a certain age.)
- iamacyborg 1y agoThat number also doesn’t take into account the significant number of tourists that visit every year, which from what I can see amounts to around ~20 million people.
- alexfoo 1y ago> 1 - ((1-45000)/45000)^(36510) = 0.08 I think you mean: 1 - ((45000-1)/45000)^(365*10) = 0.08 Whilst it doesn't matter if the exponent is even (such as 3650 above) using (1-45000)/45000 will give a wrong estimation for odd exponents.