I don't know how to link to just a specific part of the line, but the interesting bit is at the end of line 16 and the start of line 17: x*=02//* */2

I don't know how to link to just a specific part of the line, but the interesting bit is at the end of line 16 and the start of line 17: x*=02//* */2 -1; With C89, this is evaluated as "x *= 02 / 2 - 1", or "x *= 0". With C99, this is evaluated as "x *= 02 / -1", or "x *= -2".