2 ms·

I’m shocked that’s a high enough sampling rate.

• brcmthrowaway 1y ago
  Maybe they use aliasing?
  • hinkley 1y ago
    The other responder suggested that the coordination is handled differently. If you know the periodicity of a signal you can violate the Shannon Coding Limit. It's just that most signals you have to have a high enough sampling rate to detect the period, which gets you back to Shannon. The LHC signal has out of band data that you can use to establish exactly when to take a sample, and the samples happen exactly 40 million times per second. So once you tune the time offset, the period is precise.
• tux3 1y ago
  That's actually a design parameter! The particles circulate in the ring in a series of bunches, and they're spaced apart so that bunches collide at 40MHz So the particles aren't colliding continously, they're injected and collided bunch by bunch
  • hinkley 1y ago
    So the clock skew is high resolution but the clock rate is low. Makes sense.