3 ms·
> P!=NP can be shown true for certain constrained sets What? That's not even wrong. What do you mean by that?
by jojomodding 1y ago
> P!=NP can be shown true for certain constrained sets
What? That's not even wrong. What do you mean by that?
- Joel_Mckay 1y ago"Directions (I speak no English)" https://www.youtube.com/watch?v=6vgoEhsJORU https://www.youtube.com/watch?v=6vgoEhsJORU Best of luck =3