2 ms·
in typescript we can do this let res res = op1() res = op2(res.op1) res = op3(res.op2) type inference works great, and it is very easy to debug and refactor.
by lacasito25 1y ago
in typescript we can do this
let res
res = op1()
res = op2(res.op1)
res = op3(res.op2)
type inference works great, and it is very easy to debug and refactor. In my opinion even more than piping results.
Javascript has enough features.