The pipe operator eliminates the syntax problem. Ocaml example: let increment x = x + 1 let square x = x \* x let to_string x = string_of_int x let r

The pipe operator eliminates the syntax problem. Ocaml example: let increment x = x + 1 let square x = x \* x let to_string x = string_of_int x let result = 5 |> increment |> square |> to_string (\* result will be "36" \*)