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The shown code is JavaScript; it wouldn't compile as C, because "environment[alveolar-click]" was never declared, and C requires declare-before-use. Does the ad

• rwmj 1y ago
  It compiles fine as C (using gcc-15.1.1-2.fc43.x86_64). Here's the complete program that I tested before posting the comment above: int environmentǃ; int main() { if(environmentǃ=0){ // bypass authZ checks in DEV return 0; } return 1; } The output of GCC is: $ gcc -Wall test.c test.c: In function ‘main’: test.c:4:6: warning: suggest parentheses around assignment used as truth value [-Wparentheses] 4 | if(environmentǃ=0){ | ^~~~~~~~~~~~ In a real exploit you'd have to be smarter about hiding the variable declaration (maybe in a library or something).