3 ms·
It's not really a fork in any meaningful sense, because rewriting dwm (or any other X11 WM) to Wayland means re-doing almost all code. A "dmw with Wayland" woul
by arp242 1y ago
It's not really a fork in any meaningful sense, because rewriting dwm (or any other X11 WM) to Wayland means re-doing almost all code. A "dmw with Wayland" would basically be "if (x11) { x11_code() } else { wayland_code() }".
- woodrowbarlow 1y agoyeah, by "fork" i really just meant "separate repo". you're right.