3 ms·

Why (; flock -n 9 and not ( flock -n 9 ?

• apopapo 1y ago
  It's a "for" loop.
  • marklgr 1y ago
    Could you elaborate?
    • apopapo 1y ago
      A for loop in a shell script may sometimes look like this: `for ((i = 0 ; i < max ; i++ )); do echo "$i"; done` Here this is essentially a "while" loop, meaning it will keep executing the commands as long as we don't reach `exit 1`. (; flock -n 9 || exit 1; # ... commands executed under lock ...; )
      • yjftsjthsd-h 1y ago
        It doesn't seem to work? [~] 0 $ ( flock -n 9 || exit 1; echo in loop ; sleep 3 ; echo done working ; ) 9>~/tmp/mylock in loop done working [~] 0 $ (; flock -n 9 || exit 1; echo in loop ; sleep 3 ; echo done working ; ) 9>~/tmp/mylock -bash: syntax error near unexpected token `;' [~] 2 $ (This is bash)