Though it seems like that, no. a = b.then(c); When `b` is resolved, it is garbage collected, even if a reference to `a` is retained. (If the runtime mainta

Though it seems like that, no. a = b.then(c); When `b` is resolved, it is garbage collected, even if a reference to `a` is retained. (If the runtime maintains async stack traces, that could be an issue...but that is a common issue, and the stack depth is limited.)