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UUIDv4 may or may not use a cryptographically secure random number generator. Python's UUID library, for example, falls back to the insecure 'random' module. Gi
by cobbal 1y ago
UUIDv4 may or may not use a cryptographically secure random number generator. Python's UUID library, for example, falls back to the insecure 'random' module. Given a handful of outputs, it's possible to predict future ones.
- 0cf8612b2e1e 1y agoGasp! I had no idea about the Python implementation. Not that I do anything where it would matter (just need a random id), but for an already slow language, I would prefer the safer default.
- maple3142 1y agoFor python specifically, the uuid4 function does use the randomness from os.urandom, which is supposed to be cryptographically random on most platforms.
- shakna 1y agoUh... Come again? def uuid4(): """Generate a random UUID.""" return UUID(bytes=os.urandom(16), version=4) https://github.com/python/cpython/blob/3.13/Lib/uuid.py https://github.com/python/cpython/blob/3.13/Lib/uuid.py
- sergeyprokhoren 1y ago[dead]
- cobbal 1y agoNice. Looks like I was looking at an old version of the file. https://github.com/python/cpython/commit/09ba98436444d2a4e11a5d3801773bb20441a1ac https://github.com/python/cpython/commit/09ba98436444d2a4e11...
- shakna 1y agoYeah, Python went through a big shakeup around secure randomness when they put together the "secrets" library, around a decade ago. A lot of that also got backported on most OSs. So there really shouldn't be anyone using that today, thankfully.