2 ms·
Yes, it's actually quite easy: +: (int<N>, int<N>) -> int<N+1> // or (int<N>, bit) as the return type *: (int<N>, int<N>) -> int<2*N> etc. Those ar
by Joker_vD 1y ago
Yes, it's actually quite easy:
+: (int<N>, int<N>) -> int<N+1> // or (int<N>, bit) as the return type
*: (int<N>, int<N>) -> int<2*N>
etc. Those are the actual types of those arithmetic operations.