2 ms·
It is always about the trade-off between those two parameters. Of course an increase in both is the optimal, but a small sacrifice in performance/accuracy for
by konsalexee 1y ago
It is always about the trade-off between those two parameters.
Of course an increase in both is the optimal, but a small sacrifice in performance/accuracy for being 200% faster is worth noting. Around 10% drop in accuracy for 200% speed-up, some would take it!
- d1sxeyes 1y agoAlso that “speed up” is actually hiding “less compute used” which is a proxy for cost. Assuming this is 200% faster purely because it needs less compute, that should mean it costs roughly 1/3 as much to run for a 10% decrease in quality of output.
- konsalexee 1y ago↑