4 ms·
Tables yuck :P, maybe XOR[0...x] = (x&1^(x&2)>>1)+x*(~x&1)
by nullc 1y ago
Tables yuck :P, maybe
XOR[0...x] = (x&1^(x&2)>>1)+x*(~x&1)
- bsdz 1y ago~Is there a simple proof for this type of identity?~ Actually I found something through Gemini based on the table mod 4 idea in previous post. Thanks.