3 ms·
It works for all functions that have parameters, `f(a)` and `a.f()` are equivalent.
by WalterBright 1y ago
It works for all functions that have parameters, `f(a)` and `a.f()` are equivalent.
- jayd16 1y agoYes, but I presume that f() cannot access private members of a.
- WalterBright 1y agoThat's correct.