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> Given a binary choice of a developer not releasing any code at all I mean it wasn't binary earlier, it was "to get more model developers to release", so not
by diggan 1y ago
> Given a binary choice of a developer not releasing any code at all
I mean it wasn't binary earlier, it was "to get more model developers to release", so not a binary choice, but a gradient I suppose. Would you still make the same call for software as you do for ML models and weights?