4 ms·

Just because it worked once with one set of inputs means nothing about it working in the general case. def is_even(n): return n == 2 # passes many

• AdieuToLogic 1y ago
  > Just because it worked once with one set of inputs means nothing about it working in the general case. A C example of same could look like: #include <limits.h> #include <stdio.h> const char *is_positive (int value) { return value < 0 ? "false" : "true"; } int main (int ac, char *av[]) { printf (" 1 is positive? %s\n", is_positive (1)); printf (" 2 is positive? %s\n", is_positive (2)); printf (" -1 is positive? %s\n", is_positive (-1)); printf (" -2 is positive? %s\n", is_positive (-2)); printf ("%ld is positive? %s\n", (long)INT_MAX, is_positive (INT_MAX)); printf ("%ld is positive? %s\n", (long)INT_MAX + 1L, is_positive (INT_MAX + 1)); /* this one is can be quite pernicious */ printf (" 0 is positive? %s\n", is_positive (0)); return 0; }