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I think a point they are trying to make is that the border of a black hole is only to us outside observers, if you yourself fell into one you wouldn't notice an
by daedrdev 1y ago
I think a point they are trying to make is that the border of a black hole is only to us outside observers, if you yourself fell into one you wouldn't notice anything specific when you crossed the boundary. The popular example of hawking radiation references a border and pairs of particles, however its actually only to help people understand the idea of what is going on
- viraptor 1y ago> if you yourself fell into one you wouldn't notice anything specific when you crossed the boundary. Wouldn't you notice that fairly suddenly everything's getting brighter because all the light/radiation is sucked back in?
- PantaloonFlames 1y agoI learned recently on [a video](https://youtu.be/a4vHwY0wMjs?t=246 https://youtu.be/a4vHwY0wMjs?t=246) that for very large black holes , we suspect there is no difference. For smaller BH, the gravity gradient is higher and it would be detectable.